Solving For Latitude

In what latitude will a departure of 200 nm corresponds to a Dlo of 4° 16'?


SOLUTION:

The formula is Cos Lat = departure ÷ Dlo

Step 1. Since Dlo is given in degrees, we have to convert it first into miles.
                Dlo = 4° 16' x 60 = 256

Step 2. Divide departure by Dlo.
               200 ÷ 256 = 0.78125

Step 3. Inverse cosine the answer in step 2

I hope you have followed. Thanks.



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• How To Solve For The Latitude Of Parallel
• Solving For Difference Of Longitude (Dlo) 

How To Solve The Latitude Of The Parallel

On a certain parallel, the distance between two meridians is 320 nm. On the equator the distance between the same two meridians is 680 nautical miles. What is the latitude of the parallel?

ANALYSIS OF THE PROBLEM:

If the distance between two meridians at the equator (latitude 0°) is 680 nm, the question then is what will be the latitude if the distance between these two meridians is 320° nm?

SOLUTION:

This is formula: Cos latitude = 320 ÷ 680

Step 1. divide 320 by 680
               
320 ÷ 680  = 0.47059

Step 2. We have to inverse cosine the answer of step 1.

0.47059 inv Cos =  61° 55.6' N or S is the answer.


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• Solving For Latitude

Rate per Hour At Latitude Carried Around Earth's The Axis

At what rate per hour is latitude 60°00' S being carried around around the earth's axis.


GIVEN:    60°00' S latitude

WHAT IS ASKED: Rate per hour at latitude 60°00' S

ANALYSIS OF THE PROBLEM:

The circumference of the earth at equator is 21,600 nm. So 900 nm/hr is the speed at the equator because earth can finish its rotation in 24 hrs according to textbooks. Though I have to say that I do not believe that the earth rotates around its axis. ( I begin to love geocentrism now).

However, the earth has an oblate spheroid shape. So there must be a difference of circumference at latitude 60°00' compared to the equator. The salient point in the problem is this: If 900 nm is the speed of the earth at the equator, how much then is its speed at latitude 60°00' S?

SOLUTION:

 Speed = 900 x Cos lat
            = 900 x Cos 60°00'
            = 450 nm

I hope this post is helpful to you. If you want to say something, your comment is very much welcome.