Your vessel receives a distress call from a vessel reporting
her position as LAT 35 01’ S; LONG 018 51’ W. Your position is LAT 35 01’ S;
LONG 021; 42’ W. Determine what will be your True Course and distance to the
vessel in distress by parallel sailing method.
Given:
λ1 = 021° 42’ W
λ2 = 018° 51’ W
Lat = 35° 01’ S
What is asked?
True course
and distance by parallel sailing
Analysis:
It is vital
to read carefully when answering a question especially when taking a board
exam. As of this particular problem we are given a hint of what kind this problem
is because it tells us that by parallel sailing method we are to answer it. But
even if, supposing, the problem does not mention parallel sailing, we can know
it is a parallel sailing by looking the given latitude. From our ship’s
latitude of 35 01’ S we go to the vessel in distress’ latitude of 35 01’ S. Our
ship’s and the vessel in distress latitude is the same. Therefore, what we have
here is a parallel sailing.
Solution:
- Solving for the distance.
Step 1. We have
to solve first for the difference of longitude (dlo). This is the rule in getting Dlo:
+ If the longitude are opposite
- If the longitude are the same
So,
λ1 = 021° 42’ W
+ λ2 = 018° 51’ W
Dlo = 002° 51’ E (The sign of Dlo is east because from
λ1 to λ2, the direction is eastward)
λ1 to λ2, the direction is eastward)
× 60 to convert it into miles
Dlo = 171 miles
Step 2. We
can now proceed to this formula in getting distance by parallel sailing.
Distance = Dlo × Cos Lat
= 171 × Cos 35° 01’
= 140 miles
- To determine the true course:
Speaking of a parallel sailing, it
is important to note that the true course is either 090° or 270°. To determine
it is by looking the sign of Dlo. Our dlo here is east, therefore, our true course
is 090°.
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