Metacentric Height
A vessel with a beam of 72 feet, has an average rolling period of 18 seconds. What would be her metacentric height?
Given:
Beam = 72 feet
Rolling period = 18 seconds
Solution:
Metacentric Height = ((Beam x 0.44) ÷ Rolling Period)²
I used 0.44 to multiply the ship's beam because the unit is feet.
GM = ((B x 0.44) ÷ RP)²
= ((72 ft x 0.44) ÷ 18)²
= (31.68 ft ÷ 18)²
= (1.76)²
= 3.09 ft will be the metacentric height(GM)
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where did 0.44 came from??
ReplyDeleteIt is from the given formula
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