A vessel at Lat. 28° 00' N, Long. 116° 00'W heads for a destination at Lat. 34° 00' N, Long. 123° 40' W. Determine the true course and distance by Middle Latitude Sailing.
Given
L1 = 28° 00' N
L2 = 34° 00' N
λ1 = 116° 00' W
λ2 = 123° 40' W
What is asked?
True course and distance by Middle Latitude Sailing.
Solution
1. Find for DLAT:
L2 = 34° 00' N
L1 = 28° 00' N
DLAT = 06° 00' N (Sign of DLAT is north because ship's direction is going north)
x 60 (to convert DLAT into miles)
360 miles
2. Find for DLO:
λ2 = 123° 40' W
λ1 = 116° 00' W
DLO = 7° 40' W (Sign of DLO is west because ship's direction is going west)
x 60 (multiply 7° by 60 to convert into miles)
420
+ 40
DLO = 460 miles
3. Solving for MLAT. We are going to add the latitudes and then divide it by 2.
L2 = 34° 00' N
L1 = 28° 00' N
62° 00'
÷ 2
MLAT = 31°
4. Solving for true course by Middle Latitude Sailing.
Tan Course = Cos MLAT x DLO
DLAT
= Cos 31° x 460miles
360 miles
= 1.09526
Course = Inv Tan 1.09526
Course = N 47.6° W (N-W because: DLAT is North; DLO is West)
To covert this course angle into True Course, we have to subtract it to 360°.
360°
- 47.6°
True Course = 312.4°
5. Solving now for the distance:
Distance = DLAT
Cos Co
= 360 miles
Cos 47.6°
Distance = 533.88 miles
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Given
L1 = 28° 00' N
L2 = 34° 00' N
λ1 = 116° 00' W
λ2 = 123° 40' W
What is asked?
True course and distance by Middle Latitude Sailing.
Solution
1. Find for DLAT:
L2 = 34° 00' N
L1 = 28° 00' N
DLAT = 06° 00' N (Sign of DLAT is north because ship's direction is going north)
x 60 (to convert DLAT into miles)
360 miles
2. Find for DLO:
λ2 = 123° 40' W
λ1 = 116° 00' W
DLO = 7° 40' W (Sign of DLO is west because ship's direction is going west)
x 60 (multiply 7° by 60 to convert into miles)
420
+ 40
DLO = 460 miles
3. Solving for MLAT. We are going to add the latitudes and then divide it by 2.
L2 = 34° 00' N
L1 = 28° 00' N
62° 00'
÷ 2
MLAT = 31°
4. Solving for true course by Middle Latitude Sailing.
Tan Course = Cos MLAT x DLO
DLAT
= Cos 31° x 460
360
= 1.09526
Course = Inv Tan 1.09526
Course = N 47.6° W (N-W because: DLAT is North; DLO is West)
To covert this course angle into True Course, we have to subtract it to 360°.
360°
- 47.6°
True Course = 312.4°
5. Solving now for the distance:
Distance = DLAT
Cos Co
= 360 miles
Cos 47.6°
Distance = 533.88 miles
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How did INV Tan 1.0956 become 47.6 west? What is INV pelase help
ReplyDeleteShift Tan to 1.0956 and the answer would be 47.6
DeleteWhen a longitude is same how can i get a dlo in mercator sailing? Or there is other way exept of mercator? Thankyou in advance
ReplyDeleteEx.
Wp7- wp8
Lat¹: 21° 17.00° long¹: 088° 12.20°
Lat²: 21° 03.00° long²: 088° 12.20°
Btw im a student
Dan vaar je pal oost 90 graden of pal west 270 graden.
Deletehi i just want to ask why it add 40 miles at the d'long when converted to distance/?
ReplyDeleteThe dlo is 7 degrees 40 minutes.
DeleteThe author is converting the dlo into miles. So 7 degrees x 60. Then just add 40 miles because 1 minute = 1 miles.
i,am very confuse how to get the exact computation icant get the answer of 1.09526 always wrong my computation even i follow the formula..=cos (31 degree x 460 different answer not the same 1,09526
ReplyDeletekindly help me sir how to calculate to correct..
maybe you are computing both directly.
Deletecompute cos 31 first
then the answer multiply it by 460 and
again once done divided it by 360