A load of 75 tons is lifted from a distance of 50 feet from the ship centerline. The displacement including the cargo is 6,000 tons and has a GM of 6 feet. Determine the list of the vessel while the cargo is held on suspension.
Given:
Displacement = 6,000 tons
Distance = 50 ft
Weight = 75 tons
GM = 6 ft
What is asked?
Angle of list
Solution:
This is the formula in getting the degree of ship's list
Given:
Displacement = 6,000 tons
Distance = 50 ft
Weight = 75 tons
GM = 6 ft
What is asked?
Angle of list
Solution:
This is the formula in getting the degree of ship's list
Tan List = Weight × Distance
Displacement × GM
Tan List = 75 tons × 50 ft
6,000 tons × 6 ft
Tan List = 3,750 ft/tons
36,000 ft/tons
List = arc tan 0.10416
List = 5.94 degrees
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