By how much can a ship submerge her load-line in water density 1004 kg/m3, if the her FWA is 185 mm?
Given:
Water density = 1004 kg/ m3
FWA = 185 mm
What is asked?
Allowable increase in ship's draft
Solution:
Allowable increase is equal to the product of fresh water allowance (FWA) times the change in density, and then divided by 25 which is constant. So this is the formula:
AI = FWA × Density change
25
AI = 185 mm × (1025 - 1004)
25
AI = 155 mm
Given:
Water density = 1004 kg/ m3
What is asked?
Allowable increase in ship's draft
Solution:
Allowable increase is equal to the product of fresh water allowance (FWA) times the change in density, and then divided by 25 which is constant. So this is the formula:
AI = FWA × Density change
25
AI = 185 mm × (1025 - 1004)
25
AI = 155 mm
You Might Also Like
- Question From Readers #1
- Question From Readers #3
- Question From Readers #5
- Question From Readers #6
- Question From Readers #7
- Question From Readers #8
- Question From Readers #16
- Question From Readers #17
- Question From Readers #18
- Question From Readers #19
- Question From Readers #20
- TPC Formula
- Change Of Trim
- Find The Initial Metacentric Height
- Moment Of Statical Stability
- Height Of Center Of Gravity
- Rolling Period Formula
- How To Solve Ship's New Draft
- Solving Shift In The Center Of Gravity
- Solving For Vessel's Trim
- Calculate Whether The Ship Is Hogging Or Sagging
- Finding Ship's New Draft
- Ship's Squat Formula
- Rolling Period Formula In Still Water
- Solving For The Righting Arm
- Reduction In GM
- Find The Height Of The Metacenter Above Keel
- Finding Displacement Of A Vessel
No comments:
Post a Comment