A bulk carrier has a displacement of 40,000 tons and the KG is 9 meters. The KN at 10° degrees shheel is 1.87 meters. What is the righting arm at this heel?
Given:
KG = 9 m
KN = 1.87 m
Angle of heel = 10 degrees
Displacement = 40,000 tons
What is asked:
Righting arm at 10 degrees heel
Solution:
GZ is the common symbol of the righting arm.
GZ = KN - (KG x Sin θ)
= 1.87 m - (9 m x Sin 10°)
= 1.87 m - 1.56283 m
GZ = 0.307 m
Given:
KG = 9 m
KN = 1.87 m
Angle of heel = 10 degrees
Displacement = 40,000 tons
What is asked:
Righting arm at 10 degrees heel
Solution:
GZ is the common symbol of the righting arm.
GZ = KN - (KG x Sin θ)
= 1.87 m - (9 m x Sin 10°)
= 1.87 m - 1.56283 m
GZ = 0.307 m
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