Rolling Period Formula In Still Water

Find the still water period of roll for a ship when the radius of gyration is 6 meters and the metacentric height is 0.5 meters.

Given: 

                           Radius = 6 m
Metacentric height (GM) = 0.5 m

What is asked?    

Rolling Period in still water              

Solution:

Still water period of roll = 2π x Radius
                                       √g x GM

                                     = 2 x 3.1416 x 6 m   
                                        √9.81 m/sec² x 0.5

                                     = 37.6992 m       
                                         √4.905 m/sec²

                                     = 17.02 seconds

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