The great circle distance from Lat. 35° 08' S, Long. 019° 26' E to Lat. 33° 16' S; Long. 115° 36' E is 4559 nautical miles and the initial course is 121° T. Determine the latitude of the vertex.
Given:
Lat1 = 35° 08' S
Lat2 = 33° 16' S
Long1 = 019° 26' E
Long2 = 115° 36' E
Initial Course = 121° T
What is asked?
Latitude of vertex
Solution:
This is the formula to getting the latitude of vertex...
Cos Lat Vertex = Cos Lat1 × Sin I.C.
Cos Lat Vertex = Cos 35° 08' × Sin 121°
Cos Lat Vertex = 0.70100
Lat Vertex = Inv Cos 0.70100
Lat Vertex = 45° 30' S
Note:
Name the Latitude vertex according to the name of Lat1.
Related Posts
Given:
Lat1 = 35° 08' S
Lat2 = 33° 16' S
Long1 = 019° 26' E
Long2 = 115° 36' E
Initial Course = 121° T
What is asked?
Latitude of vertex
Solution:
This is the formula to getting the latitude of vertex...
Cos Lat Vertex = Cos Lat1 × Sin I.C.
Cos Lat Vertex = Cos 35° 08' × Sin 121°
Cos Lat Vertex = 0.70100
Lat Vertex = Inv Cos 0.70100
Lat Vertex = 45° 30' S
Note:
Name the Latitude vertex according to the name of Lat1.
Latitude Of Vertex |
Related Posts
- Middle Latitude Sailing
- Great Circle Sailing
- Meridian Sailing
- Find DLAT And Departure
- Finding Arrival Longitude
- Solving Distance By Parallel Sailing
- Find The Vesssel's Speed
- When Ship is "On Range"
- Calculate Radar Contact's Speed
- Solving For Meridional Parts
- Upper Vertex Latitude
- Latitude Of Vertex
- Great Circle Distance And Initial Course
- Solving Distance By Parallel Sailing
- Westbound Vessel Will Cross On What In What Equator?
what if it’s negative?
ReplyDeletelike the given is:
lat1 = 8deg 50 N and the I.C. = 306.6deg T
Find out which direction you are headed, in the case of that particular question you are headed north west. In that case you’d subtract 350-306.6 to find your initial course which would be 53.4.
ReplyDelete360-306.6=53.4 **
DeletePlease formula for longitude of vertex
ReplyDeletehow did it become 45°30°
ReplyDelete