On Nov. 21, the sun bore 101° psc to an observer in DR Position Lat 41° 29' N, Long 120° 30' E, declination is 14° 32.2' S. Find the amplitude.
Given:
Latitude = 41° 29' N
declination = 14° 32.2' S
What is asked?
The amplitude
Solution:
Sin Amplitude = Sin declination
Cos latitude
= Sin 14° 32.2'
Cos 41° 29'
= 0.25099
0.74914
Sin Amplitude = 0.33504
Amplitude = 0.33504 inv Sin
= 19.57 or simply
Amplitude = E 20 S
* Why E 20 S? EAST because the sun bears 101°, which means it is rising. And SOUTH because that is the sign of the declination. So, just copy the sign of the declination.
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Given:
Latitude = 41° 29' N
declination = 14° 32.2' S
What is asked?
The amplitude
Solution:
Sin Amplitude = Sin declination
Cos latitude
= Sin 14° 32.2'
Cos 41° 29'
= 0.25099
0.74914
Sin Amplitude = 0.33504
Amplitude = 0.33504 inv Sin
= 19.57 or simply
Amplitude = E 20 S
* Why E 20 S? EAST because the sun bears 101°, which means it is rising. And SOUTH because that is the sign of the declination. So, just copy the sign of the declination.
If you find this helpful, please click the share button below to share this post to your friends. Sharing is caring...
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what about deviation and variation?
ReplyDeleteFor the example of deviation, here is my post http://oic-nwreviewer.blogspot.com/2014/01/solving-for-deviation-of-compass.html
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