A ship following a great circle track crosses the equator at long. 135° 00' E on course 051° T. If she continues along this great circle track, find the latitude and longitude of the upper vertex.
Given:
Course = 051° T
Longitude = 135° 00'
What is asked?
Latitude and longitude of the upper vertex
Solution:
In solving latitude of the upper vertex, we have to use the course to subtract to 90° or 270° depending to the direction where the ship is going.
Upper vertex latitude = 90° - 051°
= 38° 12'
For the longitude, just copy the figure and change the name of the longitude.
Given:
Course = 051° T
Longitude = 135° 00'
What is asked?
Latitude and longitude of the upper vertex
Solution:
In solving latitude of the upper vertex, we have to use the course to subtract to 90° or 270° depending to the direction where the ship is going.
Upper vertex latitude = 90° - 051°
= 38° 12'
For the longitude, just copy the figure and change the name of the longitude.
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how did he get 12 mins?
ReplyDeleteYeah, how did you get 12'?
ReplyDeleteThere was a clerical error by the author, i believe. Take a look at the photo. The course is 051.8. But the author mistyped. Instead of 051.8 true course, 051 was written.
ReplyDeleteSo 90 degree minus 051.8 degree equals 38 degrees and 12 minutes
Again, read the problem from the photo.