A cylindrical drum, 1.6 meters high has a diameter of 90 cm. Find the weight of sea water it contains if filled to capacity.
Given:
Height = 1.6 m
Diameter = 90 cm
What is asked:
Weight of sea water it would contain
Solution:
1. Convert first the 90 cm diameter into meter, and then get the radius.
90cm × 1 m = 0.90 m
100 cm
Radius = Diameter ÷ 2
= 0.90 m ÷ 2
= 0.45 m
2. We have to solve for the volume of cylindrical drum.
Volume of cylinder = (πr2) × height
= ( 3.1416 × (0.45 m)2 × 1.6 m
= 3.1416 × 0.2025 m2 × 1.6 m
= 1.01787 m3
3. We can now proceed to solve for the weight of sea water it would contain.
Weight = Density × Volume
= 1.025 tons/m3 × 1.01787 m3
= 1.04 tons
Given:
Height = 1.6 m
Diameter = 90 cm
What is asked:
Weight of sea water it would contain
Solution:
1. Convert first the 90 cm diameter into meter, and then get the radius.
90
100
= 0.90 m ÷ 2
= 0.45 m
2. We have to solve for the volume of cylindrical drum.
Volume of cylinder = (πr2) × height
= ( 3.1416 × (0.45 m)2 × 1.6 m
= 3.1416 × 0.2025 m2 × 1.6 m
= 1.01787 m3
3. We can now proceed to solve for the weight of sea water it would contain.
Weight = Density × Volume
= 1.025 tons/
= 1.04 tons
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