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What Size Of Manila Rope Is Required

Here again we have to solve another question submitted to us. This is regarding how to solve for the size of manila rope. Here it is...

What size of manila line is required to hold a weight of 932 lbs., if you use a safety factor of six? Your Answer :: 3.0? Correct Answer :: 2.5? what is the solution of this

Given:

             Load = 932 pounds
Safety Factor = 6

Find:

Size of the Manila rope

Solution:

Since the unit of weight is pounds, the formula for Manila rope's breaking strength would be C² × 900, where C is the circumference. So, BS = C² × 900.

We can solve for the Manila rope's size by using this formula:

SWL = BS
          SF

So by transposition we can have BS = SWL x SF
                                        C² × 900 = SWL x SF
                                        C² × 900 =932 x 6
                                                   C = √932 x 6
                                                              900
                                                    C = √5592
                                                              900
                                                    C = √6.21333
                                                    C = 2.49265 or simply put 2.5" is the final answer.

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3 comments:

  1. AnonymousMay 4, 2018 at 4:21 PM

    Close link chain of not less the 3/4" (or the wire rope equivalent) is required for lashing deck cargoes of timber. What size flexible wire rope would provide the strength equivalent to 3/4" chain, using a safety factor of 5?

    ReplyDelete
  2. UnknownJune 13, 2020 at 9:41 AM

    how about in metric ton unit ?

    ReplyDelete
  3. UnknownOctober 14, 2021 at 11:16 AM

    BS= C2 x 900 not C2 / 900, thank you

    ReplyDelete