While steaming at 15 knots, your vessel consumes 326 barrels of fuel oil per day. In order to reduce consumption to 178 barrels of fuel oil per day, what is the maximum speed a vessel can turn for?
Given:
Old Consumption = 326 bbls
New Consumption = 178 bbls
Old Speed = 15 kts
What is asked?
New speed
Solution:
New Consumption = New Speed3
Old Consumption Old Speed3
Old Consumption Old Consumption
New Speed3 = New Consumption x Old Speed3
³√New Speed3 = ³√1843
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Given:
Old Consumption = 326 bbls
New Consumption = 178 bbls
Old Speed = 15 kts
What is asked?
New speed
Solution:
New Consumption = New Speed3
Old Consumption Old Speed3
New Speed3 x Old Consumption = New Consumption x Old Speed3
New Speed3 x Old Consumption = New Consumption x Old Speed3
Old Consumption Old Consumption
New Speed3 x Old Consumption = New Consumption x Old Speed3
New Speed3 = New Consumption x Old Speed3
Old Consumption
= 178 x 153
326
= 178 x 3375
326
= 600750
326
New Speed3 = 1843 Apply cube root to both sides
³√New Speed3 = ³√1843
New Speed = 12.2 knots
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