While steaming at 14 knots, your vessel burns 276 bbls of fuel per day. What will be the rate of fuel consumption if you decrease speed to 11.7 knots?
Given:
Old Consumption = 276 bbls
Old Speed = 14 knots
New Speed = 11.7 knots
What is asked?
New fuel consumption
Solution:
This is the equation regarding fuel consumption. All we are going to do is to cross multiply and do some cancellation.
New Consumption = New Speed3
Old Consumption Old Speed3
New Consumption x Old Speed3 = New Speed3 x Old Consumption
New Consumption xOld Speed3 = New Speed3 x Old Consumption
Old Speed3 Old Speed3
New Consumption = New Speed3 x Old Consumption
= 1601.6 x 276
Given:
Old Consumption = 276 bbls
Old Speed = 14 knots
New Speed = 11.7 knots
What is asked?
New fuel consumption
Solution:
This is the equation regarding fuel consumption. All we are going to do is to cross multiply and do some cancellation.
New Consumption = New Speed3
Old Consumption Old Speed3
New Consumption x Old Speed3 = New Speed3 x Old Consumption
New Consumption x Old Speed3 = New Speed3 x Old Consumption
Old Speed3 Old Speed3
New Consumption x
New Consumption = New Speed3 x Old Consumption
Old Speed3
= 11.73 x 276 bbls
= 11.73 x 276 bbls
143
= 1601.6 x 276
2744
= 442041.6
2744
New Consumption = 161 bbls/day
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Why raise to the power of 3?
ReplyDeleteIt's from the formula
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