You are to load lead, SF 18 and cotton, SF 78. The available deadweight capacity is 1,600 tons of cargo and cubic capacity is 58,800 cu. ft. Disregarding broken stowage, how much of each cargo should be loaded to make her full and down?
Given:
Weight = 1,600 tons
Hold volume = 58,800 ft3
Lead stowage factor = 18
Cotton stowage factor = 78
What is asked?
Weight in tons of lead and cotton
Solution:
Weight of lead = Hold volume - (weight × SF of cotton)
SF of cotton - SF of lead
= 58,800 - (1,600 × 78)
78 - 18
= 1,100 tons
Given:
Weight = 1,600 tons
Hold volume = 58,800 ft3
Lead stowage factor = 18
Cotton stowage factor = 78
What is asked?
Weight in tons of lead and cotton
Solution:
Weight of cotton = Hold volume - (weight × SF lead)
SF of cotton - SF of lead
= 58,800 - (1,600 × 18)
78 - 18
= 30,000
60
= 500 tons
Weight of lead = Hold volume - (weight × SF of cotton)
SF of cotton - SF of lead
= 58,800 - (1,600 × 78)
78 - 18
= 1,100 tons
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