Find the DLAT and departure made good if a vessel steams for 1936 nautical miles on course 248° T.
Given:
Course = 248° T
Distance = 1936 nm
What is asked?
Dlat and departure
Solution:
This kind of problem is of a Plain Sailing. What one has to bear in mind when speaking of a Plain Sailing is a plane triangle.
Solving For Difference in Latitude
Given:
Course = 248° T
Distance = 1936 nm
What is asked?
Dlat and departure
Solution:
This kind of problem is of a Plain Sailing. What one has to bear in mind when speaking of a Plain Sailing is a plane triangle.
 |
| Plane Triangle |
Cos 68° = Dlat
Distance
Dlat = Cos 68° × 1936 nm
Dlat = 725.2 nm
Solving For Departure
Sin 68° = Departure
Distance
Departure = Sin 68° × 1936 nm
Departure = 1795 nm
 |
| Plain Sailing |
Where did the 68 come from.
ReplyDeleteYou have to convert from true to quadrant . since 248 degrees is in SW quadrant , quadrant bearing = true - 180 degrees <=> 248 - 180 = 68
DeleteAnd look at the plane triangle
Delete