A vessel enters port with an arrival draft of 11 meters at sea water density. If her FWA is 254, what will be her draft in dock water with relative density of 1.009?
ANALYSIS OF THE PROBLEM:
The vessel is from the sea going to a brackish water. Since there is a change in water density, so what will happen to its draft? In the case of a ship from the sea to a brackish water, the draft will increase.
Therefore, we can expect that the answer of this problem is more than 11 meters.
SOLUTION:
We can use the formula in getting allowable increase (AI)
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Step 1. We have to get the difference of density by subtracting sea water density by dock water density.
1.025 - 1.009 = 0.016
Step 2. Multiply the answer of step 1 by the fresh water allowance (FWA).
0.016 x 254 = 4.064
Step 3. Divide the answer of step 2 by 25.
4.016 ÷ 25 = 0.16256 meters
Step 4. We have to add the answer of step 3 to our original draft.
11 m + 0.16256 m = 11.16 meters is our final answer.
Note: We add the answer of step 3 to our original draft because the ship is coming from the sea to a brackish water.
Do you have another way of solving this problem? Why not comment and share it to us.
ANALYSIS OF THE PROBLEM:
The vessel is from the sea going to a brackish water. Since there is a change in water density, so what will happen to its draft? In the case of a ship from the sea to a brackish water, the draft will increase.
Therefore, we can expect that the answer of this problem is more than 11 meters.
SOLUTION:
We can use the formula in getting allowable increase (AI)
.jpg)
Step 1. We have to get the difference of density by subtracting sea water density by dock water density.
1.025 - 1.009 = 0.016
Step 2. Multiply the answer of step 1 by the fresh water allowance (FWA).
0.016 x 254 = 4.064
Step 3. Divide the answer of step 2 by 25.
4.016 ÷ 25 = 0.16256 meters
Step 4. We have to add the answer of step 3 to our original draft.
11 m + 0.16256 m = 11.16 meters is our final answer.
Note: We add the answer of step 3 to our original draft because the ship is coming from the sea to a brackish water.
Do you have another way of solving this problem? Why not comment and share it to us.
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Hello ,
ReplyDeleteWhy did you divide by 25 in step 3 ?
Thanks
Isn't it because he used the formula of allowable increase? AI=FWA(SW-DW)/25
DeleteThe formula says you have to divide it by 25
Deleteits the conversion from meters to millimeters
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Hello. Anybody can help me. The question is. A VESSEL DISPLACEMENT IS 81038 TONS HAS A TPC OF 65.6 TONS AND MTC OF 1003.7 KILOTONS. DRAFT FORWARD READS 13.00 M AND DRAFT AFT 14.00 M. THE TRIM TABLE FOR 100 KT SHOWS F.P (-1.46) AND A.P (4.42). CALCULATE THE NEW DRAFT FORE AND AFT IF YOU ARE TO DISCHARGE 900 tons from cargo hold no. 7?
ReplyDeletekindly share the solution sir
DeleteSame problem. You have the solution?
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