What is the approximate velocity of winds at low pressure area under Classification Scheme develop by Panofsky and Brier, if the storm central pressure is 1000 hpa?
Given: Storm central pressure = 1000
What is asked: Wind velocity
Solution:
This is the formula we are going to use: 3.9+3.5√1016 - storm central pressure. In this formula, the unit of velocity is meter/sec.If your calculator is equation type like SVPAM, just key in this directly 3.9 + 3.5√1016-1000 = 17.9 m/s. This √ is the symbol for square root. Here's how.
Step 1. Simplify first the operation inside the square root.
√1016-1000 = √16
Step 2. Key in or type this in your calculator in the correct order:
3.9 + 3.5√16 = 17.9 m/s is the wind velocity.
Note: 3.9, 3.5 , and 1016 are constant. 1000 is from the given.
See below.
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See Related Problem:
Given: Storm central pressure = 1000
What is asked: Wind velocity
Solution:
This is the formula we are going to use: 3.9+3.5√1016 - storm central pressure. In this formula, the unit of velocity is meter/sec.If your calculator is equation type like SVPAM, just key in this directly 3.9 + 3.5√1016-1000 = 17.9 m/s. This √ is the symbol for square root. Here's how.
Step 1. Simplify first the operation inside the square root.
√1016-1000 = √16
Step 2. Key in or type this in your calculator in the correct order:
3.9 + 3.5√16 = 17.9 m/s is the wind velocity.
Note: 3.9, 3.5 , and 1016 are constant. 1000 is from the given.
See below.
See Related Problem:
Excellent work. Useful in the BSMT curriculum
ReplyDeleteis it possible that the storm central pressure is higher than the given constant of 1016? It gave me an undefined answer
ReplyDelete